How do you factor completely #16x^3-10x^2-8x#?

Answer 1

#2x(8x^2-5x-4)#

Since this expression has no constant, you can factor out #2x#:
#16x^3 -10x^2 -8x#
#=2x(8x^2-5x-4)#

And in this case, you can't factor the quadratic any further, so the cubic expression is as factored as possible.

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Answer 2

To factor completely (16x^3 - 10x^2 - 8x), follow these steps:

  1. Factor out the greatest common factor, which is (2x).
  2. Rewrite the expression as (2x(8x^2 - 5x - 4)).
  3. Factor the quadratic expression (8x^2 - 5x - 4) using either the quadratic formula, completing the square, or factoring by grouping.

The factored form of (16x^3 - 10x^2 - 8x) is (2x(4x - 1)(2x + 4)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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