How do you factor by grouping #25v^2+60v+27#?

Answer 1

#(5v+3)(5v+9)#

#color(white)(..)+color(green)(60)# #color(white)(..)xx 675# #* * * * * * # #color(white)(.)1 color(white)(0)xx 675# #color(white)(.)3 color(white)(0)xx 225# #color(white)(.)5 color(white)(0)xx 135# #color(white)(.)9 color(white)(0) xx 75# #color(white)(.)15 xx 45# #=> color(red)(15)+color(red)(45) = color(green)(60)#

So we've got

#(25v^2 + color(red)(45)v) + (color(red)(15)v + 27)#
#5v(5v+9) + 3(5v+9)#
#(5v+3)(5v+9)#
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Answer 2

To factor by grouping the expression 25v^2 + 60v + 27:

  1. Multiply the leading coefficient (25) by the constant term (27): 25 * 27 = 675.

  2. Find two numbers that multiply to give 675 and add to give the coefficient of the linear term (60). These numbers are 45 and 15.

  3. Rewrite the middle term (60v) using these two numbers: 60v = 45v + 15v.

  4. Group the terms: 25v^2 + 45v + 15v + 27.

  5. Factor by grouping: (25v^2 + 45v) + (15v + 27).

  6. Factor out the greatest common factor from each group: 5v(5v + 9) + 3(5v + 9).

  7. Notice that both terms have a common factor of (5v + 9).

  8. Factor out the common factor: (5v + 9)(5v + 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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