How do you factor by grouping #12a^3+20a^2-48a#?

Answer 1

Factoring by grouping is not a method that is reasonable for an expression with 3 terms (perhaps a 4th term was intended(?))

This expression, #12a^3+20a^2-48a#, can be factored fairly simply

Extract the obvious common factor #(4a)(3a^2+5a-12)# and from there #(4a)(3a-4)(a+3)#

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Answer 2

Eva Adamson

To factor by grouping the expression (12a^3 + 20a^2 - 48a), first factor out the greatest common factor, which is 4a:

(12a^3 + 20a^2 - 48a)
(= 4a(3a^2 + 5a - 12))

Now, factor the trinomial inside the parentheses:

(3a^2 + 5a - 12)
(= (3a - 4)(a + 3))

Therefore, the factored form of (12a^3 + 20a^2 - 48a) is (4a(3a - 4)(a + 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.