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How do you factor and solve #x^2+4x+2=0#?

Answer 1

Julia Adams

#x = -0.586 " or "x = -3.414#

#x^2 +4x + 2=0# cannot be factored because there are no factors of 2 which add up to 4.

It can be solved by the method of completing the square or the quadratic formula. Completing the square will be easier.

#x^2 +4x color(magenta)(+(4/2))^2 = -2color(magenta)(+(4/2))^2 = -2 color(magenta)(+4) =2#

# (x + 2)^2 = 2" square root both sides"#

#x+2 = +-sqrt2#

#x = +sqrt2 -2 = " or "x = -sqrt2 -2#

#x = -0.586 " or "x = -3.414#

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Answer 2

Nathan Axel

To factor and solve the quadratic equation x^2 + 4x + 2 = 0, you can use the quadratic formula or complete the square method. However, if factoring is preferred, you can first try to factor the quadratic expression into two binomials. However, in this case, the quadratic expression cannot be factored easily. Therefore, the most efficient method would be to use the quadratic formula: x = [-b ± √(b^2 - 4ac)] / (2a). Plugging the coefficients from the equation into the formula, you can then solve for the values of x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.