How do you factor and solve #9x^2 + 7x - 56 = 0#?

Answer 1

(-7 +- sqrt2065)/18

#f(x) = 9x^2 + 7x - 56 = 0# #D = d^2 = b^2 - 4ac = 49 + 2016 = 2065# Since D is not a perfect square, this function can't be factored. Solve f(x) = 0 by the improved quadratic formula. #D = 2065 # --> #d = +- sqrt(2065)# There are 2 real roots: #x = -b/(2a) +- d/(2a) = - 7/18 +- sqrt(2065)/18 = (-7 +- sqrt(2065))/18#
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Answer 2

To factor and solve the quadratic equation 9x^2 + 7x - 56 = 0, you can use the quadratic formula or factor by grouping. Factoring by grouping is the simpler method here. The factored form of the quadratic equation is (3x - 8)(3x + 7) = 0. Setting each factor equal to zero gives the solutions x = 8/3 and x = -7/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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