How do you factor a perfect square trinomial #X ²+12 X +36#?

Answer 1
Since (we're implicitly assuming) it's a perfect square and the coefficient of the highest power is 1, it's just a matter of guessing factorizations of the form #(x+a)^2#.
Since we want #a^2=36# and #2a=12#, we want to use #a=6# so the factorization is #x^2+12x+36=(x+6)^2#.
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Answer 2

To factor a perfect square trinomial like (x^2 + 12x + 36), you identify that it is in the form ((x + a)^2) where (a) is half of the coefficient of (x). In this case, (a = \frac{12}{2} = 6). So, the factored form is ((x + 6)^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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