How do you factor # 8x^2-18#?

Answer 1

#2(2x+3)(2x-3)#

First, factor out the GCF (2)

#2(4x^2-9) rarr 4x^2-9# can be factored out using difference of squares:
#a^2-b^2=(a-b)(a+b)#
#a# in this case is #2x#, #b# is #3#
#(2x-3)(2x+3)#
#2(2x-3)(2x+3)#
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Answer 2

To factor ( 8x^2 - 18 ), first, find the greatest common factor (GCF) of the terms, which is 2. Then, rewrite the expression as ( 2(4x^2 - 9) ). Next, apply the difference of squares formula, which states that ( a^2 - b^2 = (a + b)(a - b) ), where ( a = 2x ) and ( b = 3 ). Thus, the factored form is ( 2(2x + 3)(2x - 3) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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