How do you factor #8x^2-17x+2#?

Answer 1

#8x^2-17x+2#

Look for integer factoring: #"Factors (ignoring signs) of " 8 = {(1,8),(2,4)}# #"Factors (ignoring signs) of " 2 ={(1,2)}#

Checking for a combination that adds up to #17# quickly gives #(8x-1)(x-2)# as the required factors

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Answer 2

Eva Adamson

To factor the quadratic expression 8x^2 - 17x + 2, you can use the factoring by grouping method. First, multiply the coefficient of the x^2 term (8) by the constant term (2), which equals 16. Next, find two numbers that multiply to give 16 and add to give the coefficient of the x term (-17). These numbers are -1 and -16. Now, rewrite the middle term (-17x) using these two numbers: -17x = -x - 16x. Group the terms accordingly: 8x^2 - x - 16x + 2. Factor by grouping: (8x^2 - x) + (-16x + 2). Factor out the greatest common factor from each group: x(8x - 1) - 2(8x - 1). Notice that (8x - 1) is a common factor in both terms. Factor it out: (x - 2)(8x - 1). Therefore, the factored form of the expression 8x^2 - 17x + 2 is (x - 2)(8x - 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.