How do you factor #8a + 6ax - 21x - 28#?

Answer 1

Hazel Anglin

#8a+6ax-21x-28 = (2a-7)(3x+4)#

This will factor by grouping once we swap the first two terms:

#8a+6ax-21x-28 = 6ax+8a-21x-28#

#color(white)(8a+6ax-21x-28) = (6ax+8a)-(21x+28)#

#color(white)(8a+6ax-21x-28) = 2a(3x+4)-7(3x+4)#

#color(white)(8a+6ax-21x-28) = (2a-7)(3x+4)#

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Answer 2

Avery Alexander

To factor the expression 8a + 6ax - 21x - 28, you can group terms with common factors. First, factor out 2 from the first two terms and factor out -7 from the last two terms. This gives you 2a(4 + 3x) - 7(3x + 4). Then, you can factor out the common factor of (3x + 4) from both terms, resulting in (2a - 7)(3x + 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.