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How do you factor #81x^2 – 36x + 4#?

Answer 1

Savannah Anderson

#81x^2-36x+4 = (9x-2)^2#

This is a perfect square trinomial in the form:

#A^2-2AB+B^2 = (A-B)^2#

as we can see:

#81x^2-36x+4 = (9x)^2-2(9x)(2)+2^2 = (9x-2)^2#

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Answer 2

Abigail Allen

To factor the expression 81x^2 - 36x + 4, we can use the quadratic formula or try factoring by grouping. Since the quadratic formula may not yield rational roots, let's try factoring by grouping:

81x^2 - 36x + 4 = (9x)^2 - 2(9x)(2) + 2^2 = (9x - 2)^2.

So, the factored form of 81x^2 - 36x + 4 is (9x - 2)^2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.