How do you factor #6xy+15x#?

Answer 1

Abigail Allen

#3x(2y+5)#

Both terms have the variable #x#,

#x(6y+15)#

Both terms can be factored by #3#,

#3x(2y+5)#

You can check if you factored correctly by multiplying through the brakctets,

#(3x*2y)+(3x+5)#

#=6xy+15x#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Abigail Allen

#3x(2y+5)#

Let's expand everything we can and then factor out common factors: #6xy+15x# #2*color(blue)(3)*color(green)(x)*y+color(blue)(3)*5*color(green)(x)#

There are #x#s in both values and a #3# for both. Let's factor those out: #3*x(2*y+5)# #3x(2y+5)#.

Just to make sure the new expression is still equal tothe old one, let's distribute the #3x# int #2y+5#. We should get #6xy+15x#

#3x(2y+5)# #2y*3x+5*3x# #6xy+15x# Yep. it's still the same! Good job!

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Julia Adams

To factor 6xy + 15x, you can first factor out the greatest common factor, which is 3x. After factoring out 3x, the expression becomes: 3x(2y + 5).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.