# How do you factor #6x^2-5x-4#?

# 6x^2-5x-4 =(3x-4)(2x+1) #

The rule to factorise any quadratic is to find two numbers such that

# {: ("factor1", "factor2", "sum"), (1,-24,-23),(2,-12,-10), (3,-8,-5) ,(4,-6,-2),(-1,24,23),(-2,12,10),(-3,8,5),(-4,6,2)

:} #

Therefore we can factorise the quadratic as follows:

Similarly if we grouped the factors the other way around we get the same answer:

This approach works for all quadratics (assuming it does factorise) , The middle step in the last section can usually be skipped with practice.

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To factor the quadratic expression 6x^2 - 5x - 4, you can use the factoring by grouping method or the quadratic formula.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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