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How do you factor #6x^2-13x+6#?

Answer 1

#6x^2-13x+6=color(green)((2x-3)(3x-2)#

#6x^2-13x+6#

We can Split the Middle Term of this expression to factorise it In this technique, if we have to factorise an expression like #ax^2 + bx + c#, we need to think of 2 numbers such that: #N_1*N_2 = a*c = 6*6 = 36# AND #N_1 +N_2 = b = -13# After trying out a few numbers we get #N_1 = -9# and #N_2 =-4# #-9*-4 = 36#, and #-9+(-4)= -13#

#6x^2-13x+6 = 6x^2-9x-4x+6#

# = 3x(2x-3) - 2(2x-3)#

#(2x-3)# is a common factor to each of the terms

#=color(green)((2x-3)(3x-2)#

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Answer 2

Kennedy Adams

To factor (6x^2 - 13x + 6), you find two numbers that multiply to (6 \times 6 = 36) and add to (-13). The factored form is ((2x - 3)(3x - 2)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.