How do you factor #5x^2 - 31x + 6#?

Answer 1

#(5x -1)(x-6)#

Find the factors of 5 and 6 which add to 31. The signs are both minus.

Choose factors and find the cross-product until a sum of 31 is found.

#"5 1 " rArr 1 xx 1 = 1# #"1 6 " rArr 5 xx 6 = 30" 30+ 1=31"#

Top row is the first factor, bottom row is the second.

#(5x -1)(x-6)#
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Answer 2

To factor the quadratic expression (5x^2 - 31x + 6), you need to find two numbers that multiply to give (5 \times 6 = 30) and add to give (-31). Then, use these numbers to rewrite the middle term and factor by grouping.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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