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How do you factor #4x^2-16x+15#?

Answer 1

#4x^2-16x+15=(2x-3)(2x-5)#

To factorize #ax^2+bx+c#, one should split middle term in two parts, so that their product is #ac# and sum is #b#.

Hence in #4x^2-16x+15#, while the product should be #4xx15=60#, sum should be #-16#. It is apparent that these are #-6# and #-10#.

Hence #4x^2-16x+15#

= #4x^2-10x-6x+15#

= #2x(2x-5)-3(2x-5)#

= #(2x-3)(2x-5)#

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Answer 2

Genesis Allen

To factor the expression 4x^2 - 16x + 15, you need to find two numbers that multiply to give 4 * 15 = 60 and add to give -16. The numbers are -10 and -6. Therefore, the factored form is (2x - 5)(2x - 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.