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How do you factor #4x^2+121=44p #?

Answer 1

Avery Alexander

Solve y = 4x^2 - 44x + 121

There is double root at# x = 11/2#

(2x - 11)^2 = 4x^2 - 44x + 121

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Answer 2

Kennedy Adams

To factor the expression 4x^2 + 121 = 44p:

Subtract 121 from both sides to rewrite the equation as: 4x^2 = 44p - 121.
Divide both sides by 4 to isolate the x^2 term: x^2 = (44p - 121) / 4.
The expression (44p - 121) / 4 cannot be factored further with integer coefficients. Therefore, the expression remains as x^2 = (44p - 121) / 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.