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How do you factor #4v^2-4v-8#?

Answer 1

Julia Adams

The answer
#v=2#

#v=-1#

#4v^2-4v-8=0#

divide it by 4

#v^2-v-2=0#

#(v-2)*(v+1)=0#

#v=2#

#v=-1#

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Answer 2

Nathan Axel

To factor the expression 4v^2 - 4v - 8, first, factor out the greatest common factor, which is 4. This leaves us with 4(v^2 - v - 2). Then, factor the quadratic expression inside the parentheses using the quadratic formula, factoring by grouping, or trial and error. Factoring v^2 - v - 2 results in (v - 2)(v + 1). Therefore, the factored form of 4v^2 - 4v - 8 is 4(v - 2)(v + 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.