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How do you factor #4m^4-64n^4#?

Answer 1

Avery Alexander

Avery Alexander

#4m^4-64n^4=4(m-2n)(m+2n)(m^2+4n^2)#

We can use the difference of squares identity:

#a^2-b^2=(a-b)(a+b)#

twice as follows:

#4m^4-64n^4#

#=4((m^2)^2-(4n^2)^2)#

#=4(m^2-4n^2)(m^2+4n^2)#

#=4(m^2-(2n)^2)(m^2+4n^2)#

#=4(m-2n)(m+2n)(m^2+4n^2)#

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Answer 2

Eva Abramson

To factor the expression 4m^4 - 64n^4, you can first notice that both terms are perfect squares. Then, apply the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b). Using this formula, the expression factors as follows:

4m^4 - 64n^4 = (2m^2 + 8n^2)(2m^2 - 8n^2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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