How do you factor #3x^2-12#?

Answer 1

#3(x-2)(x+2)#

Initially, we identify any similar terms that can be factored out of the whole equation; in this instance, that term is a three.

This gives us: #3(x^2-4)#

This can be made even simpler by applying The Difference of Squares.

#x^2-4 = 0# #x^2 = 4# #sqrt(x^2) = sqrt(4)# #x = 4, -4#

Therefore the factors of #x^2-4# are #(x-2)# and #(x+2)#

When we combine all of this, we obtain:

#3(x-2)(x+2)#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Ethan Adkins

To factor 3x^2 - 12, first factor out the greatest common factor, which is 3. This gives you 3(x^2 - 4). Next, recognize that x^2 - 4 is a difference of squares, which factors further into (x + 2)(x - 2). So, the factored form of 3x^2 - 12 is 3(x + 2)(x - 2).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.