How do you factor #2x²+5x+3#?
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To factor ( 2x^2 + 5x + 3 ), you can use the factoring by grouping method. First, multiply the coefficient of ( x^2 ) (which is 2) with the constant term (which is 3). This gives you 6. Now, find two numbers that multiply to 6 and add up to the coefficient of ( x ) (which is 5). These numbers are 2 and 3. Rewrite the middle term (5x) using these numbers:
( 2x^2 + 2x + 3x + 3 )
Now, group the terms and factor by grouping:
( (2x^2 + 2x) + (3x + 3) )
Factor out the common terms from each group:
( 2x(x + 1) + 3(x + 1) )
Now, notice that you have a common factor of ( x + 1 ). Factor it out:
( (2x + 3)(x + 1) )
So, the factored form of ( 2x^2 + 5x + 3 ) is ( (2x + 3)(x + 1) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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