How do you factor #2x²+5x+3#?

Answer 1

#2x^2+5x+3 =(x+1)(2x+3) #

#2x^2+5x+3 =2x^2+2x+3x+3 #
#=2x(x+1)+3(x+1)=(x+1)(2x+3) # [Ans]
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Answer 2

To factor ( 2x^2 + 5x + 3 ), you can use the factoring by grouping method. First, multiply the coefficient of ( x^2 ) (which is 2) with the constant term (which is 3). This gives you 6. Now, find two numbers that multiply to 6 and add up to the coefficient of ( x ) (which is 5). These numbers are 2 and 3. Rewrite the middle term (5x) using these numbers:

( 2x^2 + 2x + 3x + 3 )

Now, group the terms and factor by grouping:

( (2x^2 + 2x) + (3x + 3) )

Factor out the common terms from each group:

( 2x(x + 1) + 3(x + 1) )

Now, notice that you have a common factor of ( x + 1 ). Factor it out:

( (2x + 3)(x + 1) )

So, the factored form of ( 2x^2 + 5x + 3 ) is ( (2x + 3)(x + 1) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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