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How do you factor #2x^3-x^2-162x+81#?

Answer 1

Ethan Adkins

#=(2x-1)(x-9)(x+9)#

You could factor the bynomial

#2x^3-x^2=x^2(2x-1)#

and the bynomial

#-162x+81=-81(2x-1)#

then the polynomial is:

#2x^3-x^2-162x+81=x^2(2x-1)-81(2x-1)#

It's possible factor again:

#=(2x-1)(x^2-81)=(2x-1)(x-9)(x+9)#

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Answer 2

Ethan Adkins

To factor the expression 2x^3 - x^2 - 162x + 81, you can use the Rational Root Theorem to find possible rational roots, then use synthetic division or long division to factorize the polynomial. Alternatively, you can use the grouping method by regrouping the terms and factoring out common factors.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.