# How do you factor #2x^2 − 6x − 36#?

Use the new AC Method to factor the trinomial.

Compose factor pairs of c = -18. Proceed: (-1, 18)(-2, 9)(-3, 6). This last sum is (6 - 3 = 3 = -b). Then p = 3 and q = -6.

Answer: f(x) = 2(x + 3)(x - 6)

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To factor 2x^2 - 6x - 36, first, find the factors of the leading coefficient (2) multiplied by the constant term (-36) that sum up to the middle coefficient (-6).

The factors of 2 are 1 and 2. The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36.

After trying different combinations, the factors that satisfy these conditions are (-4) and 9.

Now, rewrite the middle term (-6x) using these factors:

2x^2 - 4x + 9x - 36

Then, factor by grouping:

2x(x - 2) + 9(x - 2)

Now, notice that both terms have a common factor of (x - 2). Factor that out:

(x - 2)(2x + 9)

Therefore, the factored form of 2x^2 - 6x - 36 is (x - 2)(2x + 9).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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