How do you factor #2x^2+5x-3#?

Answer 1

#(x+3)(2x-1)#

#"using the a-c method"#
#"the factors of - 6 which sum to + 5 are + 6 and - 1"#
#"'splitting 'the middle term gives"#
#2x^2+6x-x-3larrcolor(blue)"factor by grouping"#
#=color(red)(2x)(x+3)color(red)(-1)(x+3)#
#"take out "color(blue)"common factor "(x+3)#
#=(x+3)(color(red)(2x-1))#
#rArr2x^2+5x-3=(x+3)(2x-1)#
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Answer 2

To factor (2x^2 + 5x - 3), you find two numbers that multiply to (2 \times -3 = -6) and add to (5). These numbers are (6) and (-1). Then, you rewrite the middle term using these numbers and factor by grouping:

(2x^2 + 6x - x - 3)

Now, factor by grouping:

(2x(x + 3) - 1(x + 3))

Combine like terms:

((2x - 1)(x + 3))

So, (2x^2 + 5x - 3) factors as ((2x - 1)(x + 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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