How do you factor #2x^2+3x+4#?

Answer 1

This cannot be factored

There are no numbers which #4# and #2# can multiply together and add/subtract to #3#. However, it can be solved by using the quadratic formula #(-b+-sqrt(b^2-4(a)(c)))/(2(a))# where #a# is #2#, #b# is #3# and #c# is #4#

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Answer 2

Jace Anderson

To factor the quadratic expression (2x^2 + 3x + 4), we look for two numbers that multiply to (2 \times 4 = 8) (the coefficient of the (x^2) term multiplied by the constant term) and add up to the coefficient of the (x) term, which is 3.

However, since there are no such two numbers, the expression (2x^2 + 3x + 4) cannot be factored using real numbers. Therefore, the factored form of (2x^2 + 3x + 4) is (2x^2 + 3x + 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.