How do you factor #2x^2-2x-84#?

Answer 1

#2(x^2-x-42)#

when factorising you find a common multiple of all the digits. In this case we have #2#. #x# does not go into #84#. We then use factorisation #2(x^2-x-42)#.

Double checking our work #2(x^2)= 2x^2# #2(x)= 2x# #2(42) = 8#

Therefore = #2x^2-2x-84#

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Answer 2

Eva Abramson

2(x + 6)(x - 7)

#y = 2(x^2 - x - 42).# Factor the trinomial in parentheses. Find 2 numbers knowing their sum (b = -1) and their product (c = -42) They are: 6 and -7. Sum: 6 - 7 = -1 Product: 6(-7) = -42 y = 2(x + 6)(x - 7)

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Answer 3

Savannah Anderson

To factor the quadratic expression 2x^2 - 2x - 84, you can first factor out the greatest common factor, which is 2. Then, factor the resulting quadratic expression using the product-sum method or another appropriate factoring technique.

The factored form of 2x^2 - 2x - 84 is 2(x - 7)(x + 6).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.