How do you factor #2x^2+12xy+18y^2#?

Answer 1

the answer is #2(x+3y)^2#

first you find the GCF(greatest common factor) and that will be #2# so you'll get#2(x^2+6xy+9y^2)# and the rest inside is from what you get when you multiply #2# and the rest. now you have to figure out what two numbers that multiply to give you #9# and add to #6# so #3,3# and now you'll get #2(x+3y^2)# i shortened it but you don't have to if you have#x^2#, you don't have to do the long way, you can just figure it out from there. but this one, there's two #3s# so you can just put it like this#2(x+3y^2)#
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Answer 2

To factor (2x^2 + 12xy + 18y^2), first, factor out the greatest common factor, which is (2). This leaves us with (2(x^2 + 6xy + 9y^2)). Now, we can factor the quadratic expression inside the parentheses. Since it is a perfect square trinomial, it factors into ((x + 3y)^2). Therefore, the factored form of (2x^2 + 12xy + 18y^2) is (2(x + 3y)^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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