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How do you factor #2a^3-128#?

Answer 1

#(a - 4)(a^2 + 4a + 16)#

Apply the algebraic formula: #a^3 - b^3 = (a - b) (a^2 + ab + b^2)# #y = 2(a^3 - 64) = 2(a^3 - 4^3) = 2(a - 4)(a^2 + 4a + 16)#

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Answer 2

Isaiah Anthony

To factor 2a^3 - 128, you can first factor out the greatest common factor, which is 2. This leaves you with 2(a^3 - 64). Then, you can recognize that a^3 - 64 is a difference of cubes, which can be factored as (a - 4)(a^2 + 4a + 16). Therefore, the factored form of 2a^3 - 128 is 2(a - 4)(a^2 + 4a + 16).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.