How do you factor #28x^3 +17x^2 -30x + 6#?
Refer to explanation
Using the following "clever" method
We try to factor it as a product of a polynomial of first degree and one of second degree as follows
Now doing the calculation in the RHS of the equation and equating the correspoding parts we get
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To factor the expression (28x^3 +17x^2 -30x + 6), you can use grouping:
Group the terms: ( (28x^3 +17x^2) + (-30x + 6) )
Factor out the greatest common factor from each group: ( x^2(28x + 17) - 6(5x - 1) )
Notice that both terms have a common factor of (5x - 1), so we can factor that out: ( (x^2 - 6)(5x - 1) )
So, (28x^3 +17x^2 -30x + 6) factors into ((x^2 - 6)(5x - 1)).
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To factor ( 28x^3 + 17x^2 - 30x + 6 ):
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Group the terms: ( (28x^3 + 17x^2) + (-30x + 6) )
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Factor by grouping: ( x^2(28x + 17) - 6(5x - 1) )
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Factor out the common factors: ( x^2(28x + 17) - 6(5x - 1) )
Therefore, the factored form of ( 28x^3 + 17x^2 - 30x + 6 ) is ( x^2(28x + 17) - 6(5x - 1) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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