How do you factor #27(K^3)-8#?

Answer 1

#27(K^3) - 8 = (3K - 2)(9K^2 + 6K + 4)#

This is an example of the difference of two cubes. Look for the pattern here:

#x^3 - y^3 = (x - y)(x^2 + xy + y^2)#
#x^3 + 8 = (x + 2)(x^2 - 2x + 4)#

Hint: There are 2 brackets in the answer. The first is easy to find. The second bracket is formed from the first bracket.

Using the same pattern...

#27(K^3) - 8 = (3K - 2)(9K^2 + 6K + 4)#
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Answer 2

To factor (27k^3 - 8), you can use the difference of cubes formula, which states that (a^3 - b^3 = (a - b)(a^2 + ab + b^2)).

So, applying this formula to (27k^3 - 8), we get:

[ 27k^3 - 8 = (3k)^3 - 2^3 ]

Therefore, (a = 3k) and (b = 2), so we have:

[ 27k^3 - 8 = (3k - 2)(9k^2 + 6k + 4) ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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