How do you factor #27(K^3)-8#?
This is an example of the difference of two cubes. Look for the pattern here:
Hint: There are 2 brackets in the answer. The first is easy to find. The second bracket is formed from the first bracket.
Using the same pattern...
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To factor (27k^3 - 8), you can use the difference of cubes formula, which states that (a^3 - b^3 = (a - b)(a^2 + ab + b^2)).
So, applying this formula to (27k^3 - 8), we get:
[ 27k^3 - 8 = (3k)^3 - 2^3 ]
Therefore, (a = 3k) and (b = 2), so we have:
[ 27k^3 - 8 = (3k - 2)(9k^2 + 6k + 4) ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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