How do you factor #22x^2 + 51x - 10#?

Answer 1

Factor: #y = 22x^2 + 51x - 10#

Ans: (11x - 2)(2x + 5)

I use the new AC Method. Factored form: y = 22(x + p)(x + q). Converted trinomial: #y' = x^2 + 51x - 220.# Find 2 numbers p' and q' knowing sum (-51) and product (-220). p' and q' have opposite signs. Factor pairs of (220) --> ...(-2, 49)(-4, 55). This sum is 51 = b. Then, p' = -4 and q' = 55. Therefor: #p = -4/22 = -2/11# and #q = 55/22 = 5/2#

y = 22(x - 2/11)(x + 5/2) = (11x - 2)(2x + 5)

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Genesis Allen

To factor (22x^2 + 51x - 10), you can use the factoring by decomposition method or the quadratic formula.

Factored form: ( (2x - 1)(11x + 10) )

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.