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How do you factor #16y^2-49#?

Answer 1

Eva Abramson

It is

#16y^2-49=(4y)^2-7^2=(4y+7)(4y-7)#

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Answer 2

Eva Adamson

To factor 16y^2 - 49, you can use the difference of squares formula, which states that (a^2 - b^2 = (a + b)(a - b)):

(16y^2 - 49 = (4y)^2 - 7^2)

Now, apply the difference of squares formula:

(= (4y + 7)(4y - 7))

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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