How do you factor #153r+170s-51#?

Answer 1

#17(9r+10s-3)#

Understanding the multiplication tables is necessary for factoring; otherwise, it turns into a laborious process requiring the reduction of every number to its prime factors.

#153r +170s -51#
Always look for a common factor first. Only 51 is a number you might be familiar with. #51 = 3 xx 17# If you are not, use the rules for divisibility to find one factor.
#51# is odd so 2 is not a factor
#5+1 = 6# so 51 is divisible by 3.
#51 = 3 xx17" "# Both factors are prime, so we cannot factor further.
Now we have a clue: #17# is also a factor of #170# #153# is 17 less than 170 and is therefore #9xx17#

We now share a factor in common:

#17(9r+10s-3)#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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