How do you factor #12x²-3x#?

Answer 1

#3x(4x-1)#

We have to find the combined #color(blue)"common factor"# of the 2 terms.
The factors of 12 are #1,2,color(red)(3),4,6,12#
The factors of 3 are #1,color(red)(3)#
Hence the common factor of 12 and 3 is #color(red)(3)#
#x^2=x xx color(magenta)(x)" and " x=1xxcolor(magenta)(x)#
Hence the common factor of #x^2" and " x" is " color(magenta)(x)#

The combined common factor of the 2 terms is 3x

#rArr12x^2-3x=3x(4x-1)#
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Answer 2

To factor the expression 12x² - 3x, you first need to find the greatest common factor (GCF) of the terms. In this case, the GCF is 3x. Then, you divide each term by the GCF:

12x² ÷ 3x = 4x -3x ÷ 3x = -1

So, factoring out the GCF, the expression becomes:

3x(4x - 1)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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