How do you factor #12x^2+69x+45#?
The equation can be factorised to
gives
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f(x) = 3(4x + 3)(x + 5)
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To factor (12x^2+69x+45), you can first look for two numbers that multiply to (12 \times 45 = 540) and add up to (69). These numbers are (15) and (36).
Then, rewrite the middle term (69x) as (15x + 54x).
Next, group the terms: (12x^2 + 15x + 54x + 45).
Now, factor by grouping: (3x(4x + 5) + 9(4x + 5)).
Finally, factor out the common binomial factor ((4x + 5)): ((3x + 9)(4x + 5)).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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