How do you factor #12m^2n^2p^2-mnp-6#?

Answer 1

#3 times 2^2 times (m n p +2/3)times (m n p - 3/4)#

Making #x = m n p# the resulting equation #12 x^2-x-6=0# has roots: #x = -2/3# and #x= 3/4# So we can represent #12 x^2-x-6 = 12(x+2/3)(x-3/4)# The final factorization is #3 times 2^2 times (m n p +2/3)times (m n p - 3/4)#

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Answer 2

Abigail Allen

To factor the expression 12m^2n^2p^2 - mnp - 6, you can first look for common factors among the terms. Then, you can use techniques like factoring by grouping or quadratic factoring. Would you like a step-by-step explanation?

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.