How do you factor 10t² + t - 2?

Answer 1

Ethan Adkins

Given the expression #10t^2 + t -2# we could set the given expression equal to zero and use the quadratic roots formula

#t= (-b+-sqrt(b^2-4ac))/(2a)#

which evaluates as #t= -1/2# or #t= 2/5#

So #(t+1/2)# and #(t-2/5)# are both factors of the given expression

with the remaining factor #=10#

#10t^2 + t -2 = 10(t+1/2)(t-2/5)#

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Answer 2

Nathan Axel

To factor (10t^2 + t - 2), you can look for two numbers that multiply to give you (10 \times (-2) = -20) and add up to (1) (the coefficient of (t)). These numbers are (5) and (-4). Then, you can rewrite the middle term using these numbers and factor by grouping. The factored form is ((5t - 2)(2t + 1)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.