# How do you express the function #h(x)=(x + 3)^6# in the form f o g?

To express the function ( h(x) = (x + 3)^6 ) in the form ( f \circ g ), we need to find two functions ( f(x) ) and ( g(x) ) such that when you apply ( g ) first and then ( f ) to the result, you get ( h(x) ).

Let's choose ( f(x) = x^6 ) and ( g(x) = x + 3 ).

When we apply ( g ) first and then ( f ) to the result, we get:

[ f(g(x)) = f(x + 3) = (x + 3)^6 ]

So, ( h(x) = (x + 3)^6 ) is expressed in the form ( f \circ g ).

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This can be done in an infinite amount of ways. However, the easiest way is to use the sixth power to your advantage.

Other variations include:

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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