# How do you evalute #tan^-1 (-sqrt(3))#?

the

this is the same for

this means that

here, an equilateral triangle is drawn and bisected to make two right-angled triangles.

since the outer triangle is equilateral, there is a

here, the adjacent is

the opposite side, calculated using Pythagoras' Theorem, is

(in the diagram, it is shown as

which is

following the law of surds where

therefore,

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To evaluate (\tan^{-1}(-\sqrt{3})), we use the inverse tangent function, also known as arctan.

[\tan^{-1}(-\sqrt{3}) = -\frac{\pi}{3}]

The arctan function returns an angle in radians whose tangent is the given number. Since (-\sqrt{3}) is the negative of the tangent of (\frac{\pi}{3}), the result is (-\frac{\pi}{3}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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