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How do you evaluate #x-(absz+x)# when x=6, z=3?

Answer 1

Aurora Arias

#-3#

First step is to evaluate the contents of the bracket and subtract the result from x.

The #color(blue)"absolute value"# is always positive since it is a measure of the distance of a value from zero.

#"That is " |-4|=|4|=4# since both - 4 and 4 are 4 units from zero.

Substitute given values into the expression.

#rArr(|3|+6)=(3+6)=9larr" evaluation of bracket"#

#rArr6-9=-3larr" evaluation of expression"#

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Answer 2

Gianna Caruso

To evaluate the expression ( x - (\lvert z \rvert + x) ) when ( x = 6 ) and ( z = 3 ), substitute the given values into the expression:

[ 6 - (\lvert 3 \rvert + 6) ]

[ = 6 - (3 + 6) ]

[ = 6 - 9 ]

[ = -3 ]

So, the value of the expression is -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.