# How do you evaluate #(x^3 + 3x^2 + 16x+48) \div (x+3#)?

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To evaluate the expression ((x^3 + 3x^2 + 16x + 48) \div (x + 3)), you can use polynomial long division or synthetic division. Here's the result using polynomial long division:

- Divide the first term of the dividend by the first term of the divisor: (\frac{x^3}{x} = x^2).
- Multiply the entire divisor by (x^2), and subtract it from the dividend: ((x^2)(x + 3) = x^3 + 3x^2). (x^3 + 3x^2 + 16x + 48 - (x^3 + 3x^2) = 16x + 48).
- Repeat the process with the new polynomial (16x + 48) as the dividend: Divide the first term of the new dividend by the first term of the divisor: (\frac{16x}{x} = 16).
- Multiply the entire divisor by 16, and subtract it from the new dividend: (16(x + 3) = 16x + 48). (16x + 48 - 16(x + 3) = 16x + 48 - 16x - 48 = 0).

The result is (x^2 + 16), with no remainder. Therefore, the quotient of ((x^3 + 3x^2 + 16x + 48) \div (x + 3)) is (x^2 + 16).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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