How do you evaluate #x^2+2x-1# when #x=2#?
So, #x^2-2x-1 = (2)^2+2(2)-1 = 4+4-1 = 7#
By signing up, you agree to our Terms of Service and Privacy Policy
To evaluate ( x^2 + 2x - 1 ) when ( x = 2 ), substitute ( x = 2 ) into the expression:
( 2^2 + 2 \times 2 - 1 )
which equals
( 4 + 4 - 1 = 7 ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- A person has a total of 65 coins in a jar consisting of quarters and nickles. The total value of the coins is $10.25. How many quarters and nickles does the person have?
- What is the range of # f(x) = -3x-1#?
- How do you simplify #0.23-(-1.46)#?
- How do you solve #2- ( x + 4) = x - 3#?
- How do you find the domain and range for #y=x^2+3#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7