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How do you evaluate the power #(2/3)^2#?

Answer 1

Benjamin Altschul

#4/9#

#(2/3)^2=(2/3)xx(2/3)=(2^2)/(3^2)#

#=(2xx2)/(3xx3)#

#=4/9#

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Answer 2

Nova Allen

#(2/3)^2# would be evaluated as #4/9#

In order to solve this problem, you first need to know that and number with an exponent of two means that the number with the exponent is multiplied by itself two times. For example, if is was #5^2#, then we would expand it to be #5 * 5# to get an answer of #25#.

So for this espressions... You would evaluate #(2/3)^2# by expanding it to become #2/3 * 2/3# and multiplying out as normal to get #4/9# as your answer.

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Answer 3

Benjamin Altschul

To evaluate ( \left(\frac{2}{3}\right)^2 ), you raise the fraction ( \frac{2}{3} ) to the power of 2, which means multiplying it by itself.

[ \left(\frac{2}{3}\right)^2 = \frac{2}{3} \times \frac{2}{3} ]

To multiply fractions, you multiply the numerators together and the denominators together.

[ \left(\frac{2}{3}\right)^2 = \frac{2 \times 2}{3 \times 3} ]

[ \left(\frac{2}{3}\right)^2 = \frac{4}{9} ]

So, ( \left(\frac{2}{3}\right)^2 ) equals ( \frac{4}{9} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.