How do you evaluate the power #(-0.8)^2#?

Answer 1

Multiply # -0.8 xx -0.8#

The answer is + .64

The exponent #x^2# means to multiply the x by itself. Or to multiply the number by itself

Since x in this instance = -0.8,

#-0.8 xx -0.8# = the evaluation of #(-0.8)^2#
# - xx - = +# so the answer is positive not negative.
#.8 xx .8 # = .64

Thus, the response is +.64.

Writing the issue down as a fraction is another way to approach it.

#- 8/10 xx - 8/10 # = # ( - xx - ) xx ( 8 xx 8)/ (10xx10)# This gives
# + 64/100# as a decimal this is + 0.64
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Answer 2

To evaluate the power ((-0.8)^2), you simply square the base, which is (-0.8). Therefore, ((-0.8)^2 = (-0.8) \times (-0.8) = 0.64).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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