How do you evaluate the limit #(x+5)/(2x^2+1)# as x approaches #oo#?
Zero
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To evaluate the limit of (x+5)/(2x^2+1) as x approaches infinity, we can use the concept of limits. By dividing every term in the expression by x^2, we get (1/x + 5/x^2)/(2 + 1/x^2). As x approaches infinity, 1/x and 5/x^2 both approach zero. Thus, the expression simplifies to 0/2, which equals zero. Therefore, the limit of (x+5)/(2x^2+1) as x approaches infinity is zero.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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