# How do you evaluate the limit #-x^3+10x^2-33x+38# as x approaches #3#?

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To evaluate the limit of the function -x^3+10x^2-33x+38 as x approaches 3, we substitute 3 into the function and simplify the expression.

By substituting x = 3 into the function, we get: -(3)^3 + 10(3)^2 - 33(3) + 38

Simplifying this expression, we have: -27 + 90 - 99 + 38

Combining like terms, we get: 2

Therefore, the limit of the function as x approaches 3 is 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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