How do you evaluate the limit #x^(1/x)# as x approaches #oo#?
You can write:
Then you have:
and so:
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The limit of x^(1/x) as x approaches infinity is equal to 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you evaluate #[x/(x^2-d^2)^(1/2)] # as x approaches negative infinity?
- How do you find the Limit of #ln(n+1) - ln(n) # as n approaches infinity?
- How do you evaluate the limit #tanx/(4x)# as x approaches #0#?

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