# How do you evaluate the limit #x/(1+4x^2)# as x approaches #oo#?

By signing up, you agree to our Terms of Service and Privacy Policy

The limit of x/(1+4x^2) as x approaches infinity is 0.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- For what values of x, if any, does #f(x) = 1/((x+1)(x-6)) # have vertical asymptotes?
- How do you find the limit of # [1/(3+X)]- (1/3) ÷ X# as x->0?
- How do you find the limit of #(1/x)^x# as x approaches infinity?
- How do you find the limit of #(3x+1/x) - (1/sinx)# as x approaches 0 using l'hospital's rule?
- How do you find the limit of #ln ( (x+1) / x )# as x approaches infinity?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7