How do you evaluate the limit #(t^2-2t-15)/(t-5)# as t approaches #2#?
Christopher Allersplug t = 2 straight into the equation
plug t = 2 straight into the equation as it is continuous through this limit
and you get 5
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Adam AdkinsTo evaluate the limit (t^2-2t-15)/(t-5) as t approaches 2, we can substitute the value of t into the expression. Plugging in t=2, we get (2^2-2(2)-15)/(2-5) = (4-4-15)/(-3) = -15/-3 = 5. Therefore, the limit is equal to 5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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