# How do you evaluate the limit #sinx/(5x)# as x approaches #0#?

The limit is

This is not possible, so we us l'Hôpital's rule.

graph{sinx/(5x) [-1.884, 1.96, -0.53, 1.392]}

By signing up, you agree to our Terms of Service and Privacy Policy

The limit of sinx/(5x) as x approaches 0 is equal to 1/5.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you evaluate the limit #(t^2-2t-15)/(t-5)# as t approaches #2#?
- Do polynomial functions have asymptotes? If yes, how do you find them?
- What is the limit of #sin^4(x)/x^0.5# as x goes to infinity?
- What is the limit of #(2x^2+3)^(1/2) - (2x^2-5)^(1/2)# as x approaches infinity?
- What is the limit of #sinx / x# as x goes to infinity?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7