How do you evaluate the limit #sinx/(5x)# as x approaches #0#?
The limit is
This is not possible, so we us l'Hôpital's rule.
graph{sinx/(5x) [-1.884, 1.96, -0.53, 1.392]}
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The limit of sinx/(5x) as x approaches 0 is equal to 1/5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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