Home > Calculus > Determining Limits Algebraically

How do you evaluate the limit #s^2/2+3s+11/2# as s approaches #0#?

Answer 1

Scarlett Allison

The function is continuous in #s = 0#, so the limit equals the value.

For #s = 0#, you have

#lim_(s -> 0)(s^2/2 + 3 * s + 11/2) = 0^2/2 + 3 * 0 + 11/2 = 11/2#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Emma Aldridge

To evaluate the limit of s^2/2 + (3s + 11)/2 as s approaches 0, we substitute 0 for s in the expression. This gives us (0^2)/2 + (3(0) + 11)/2, which simplifies to 0/2 + 11/2. Further simplifying, we get 0 + 11/2, which equals 11/2. Therefore, the limit of the expression as s approaches 0 is 11/2.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.